User blog:Gwynbleiddd/Thor destroys Sokovia

The building is 17 floors, each floor should be around 3 m.

So the height of the building is 51 m

From the second image:

The building is 43 px = 51 m

Diameter of Sokovia is 1173 px = 1391 m

Radius of Sokovia = diameter/2 = 695.5 m

Volume of Sokovia ( i assume it's a hemisphere) = 2/3* π*R^3

Volume= 704611969.83 m^3

Volume (in cm^3) = 7.0461197*10^14 cm^3

Fragmetation energy = Volume* 8 = 5.6*10^15 Joules (Small City level)

Violent Fragmetation energy =Volume*120 = 8.455*10^16 Joules (City level)

Thanks PancakeExterminator for providing the images.

Using kinetic energy


There are two ways to measure the feat.

1: Thor neutrilized Sokovia's kinetic energy (thus there was not so much damage)

Sokovia was falling for 41 seconds before thor destroyed it, using this formula we can find it's speed:

U=g*t ( i assume it's doing a free fall because there are rocket engines that push it)

U=10*41= 410 m/s

Mass of sokovia= density*volume= 704611969.83* 2800 =1.9729135*10^12 kg

KE=1/2*m*U^2 = 1.65*10^17 Joules (City level)

2.Finding the KE of the debris after thor blew it up.

Blue line (Sokovia's diameter) is 1143 px =1391 m

Red line (distance the debris traveled in around 1 second) is 532 px= 647 m

Speed of the debris= around 647 m/s

KE= 1/2*m*u^2=3.97*10^17 (City level)